Gamma-ray lines
In collaboration with: Jürgen Knödlseder, Daniel Schaerer, Peter von Ballmoos and Geoges Meynet
Please, refer any use of this server as:
Cerviño et al. 2000, A&A 363, 970 (http://www.laeff.inta.es/users/mcs/SED)
Hello;
welcome to the CMHK's result for Gamma-ray lines.
Here we show the output files from the models used in Cerviño et al. (2000) paper about 26Al and 60Fe.:
The data files contains:
Age in Myrs
log NHlyc: log of the number of Q(H0) photons s-1 Mo-1
log NHelyc: log of the number of Q(He0) photons s-1 Mo-1
# O, # WR, # WN, # WC, # RSG, # SN: Number of different types of stars in Mo-1
M_0: Initial mass of the most massive star in the cluster.
M_t: Current mass of the most massive star in the cluster.
26Al*tot, 26Al*, 26Alwr, 26AlSnI, 26AlSNII, 26AlSN, 26Al:
Masses of 26Al emitted by all stars, non-WR stars, WR, SN I,
SN II, all SN, and stars+SN in units of MoAl Myr-1 Mo-1. It corresponds to ydot26 in the paper.
60FeSnI, 60FeSNII, 60Fe:
Masses of 60Fe emitted by SN I, SN II, and all SN in units of MoFe Myr-1 Mo-1. It corresponds to ydot60 in the paper.
26Aldec, Fe60dec: Emissivities (decay reates, Ydot in the paper, related with the flux of the line) of 26Al and 60Fe in Mo Myr-1 Mo-1.
For use it you must multiply the output by the ammount of gas transformed in stars, and you must take into account that:
The models assume a Salpeter IMF slope in the mass range 2 - 120 Mo,
so the multiply factor is the ammount of gas transformed in stars in this mass range.
The output has been normalized to:
Instantaneous Burst (IB) case:
The amount of gas transformed in stars
since the onset of the burst
(click here to get the IB table)
CSFR:
The amount of gas transformed in stars
since the onset of the burst:
If you have a CSFR
of 1Mo/yr and the burst have an age of 20Myrs, you must multiply by
1Mo/yr x 20 106Myrs = 2 107Mo.
If you do not know the age, multiply each observable by
the age (collumn 1). The resulting table is then normalized by
a CSFR = 1Mo/Myr. The final ages must show a constant value with time
and you can use it (assuming that it is an equilibrium value).